WebNow we have $12$ locations. In the first seat we have $12$ potential students, in the second we have $11$, in the third we have $10$, and so on. That gives us $12!$ ways of arranging $12$ students in $12$ seats. Multiplying the number of possible seats with the number of combinations of students in those seats, we get the result: $12!\cdot{30 ... WebAug 2, 2024 · The numbers of seats in the first 12 rows of a high-school auditorium form an arithmetic sequence. The first row has 9 seats. The second row has 11 seats. a) Write a …
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WebThe number of seats in the first 12 rows of a high-school auditorium form an arithmetic sequence. The first row has 9 seats the second row has a 11 seats a) Write a recursive formula to represent the sequence b) write an explicit formula to represent the sequence c) how many seats are in the 12th row Expert Answer 100% (1 rating) WebThe numbers of seats in the first 12 rows of a high-school auditorium form an arithmetic sequence. The first row has 9 seats. The second row has 11 seats. a) Write a recursive … games online bike two player
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WebA limited number of seats in Sections SS2-SS5 are typically reserved for Alabama students, which only adds to the atmosphere on that side of the field. On both sides of the field you'll find bench-style seating and roughly 35 rows in each section. For the best value, choose seats in the first 12 rows on the southwest side of the field. WebMar 23, 2016 · The number of seats in the first 12 rows of a high-school auditorium form an arithmetic sequence. The first row has 9 seats. The second row hass 11 seats. a.) Write a … WebIf you have 5 people and 8 seats where order matters, you can put the first person in any of the 8 seats (put any of the 8 seats under person 1), the second person in any of the remaining 7 (put any of the remaining seven seats under the second person), etc. This gives 8*7*6*5*4=8!/3!= 8 P 5 ( 5 votes) Nitin Kumar 5 years ago black gold shotgun cartridges